Asked by hriday
the ground stste energy of H- atom is -13.6 eV. the energy needed to ionise H- atom from its second excited state is
1.51 eV
3.4 eV
13.6 eV
12.1 eV
1.51 eV
3.4 eV
13.6 eV
12.1 eV
Answers
Answered by
drwls
That state is 13.6 eV/(2^2) = 3.4 eV below the ionization limit, since the principal quantum number is 2.
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