Asked by Enrique

hi

At a particular temperature, K = 1.00 102 for the following reaction.
H2(g) + I2(g)= 2 HI(g)

In an experiment, 1.73 mol H2, 1.73 mol I2, and 1.73 mol HI are introduced into a 1.00 L container. Calculate the concentrations of all species when equilibrium is reached.
H2


okay so i set up an ICE table

and the HI at equillibrium would be



1.73+2x M right?? i got the concentration of the reactants i just need help with the HI especially when there is two as the coefficient!

thanks!
Answered by DrBob222
It seems to me that if K = 1.00 that the final concentrations will be 1.73 M for each since
Kc = 1.00 = (HI)^2/((H2)(I) = (1.73)^2/(1.73)(1.73) = 1.00
Answered by Sydney
That's correct. Just play around with the number of sig figs (there should be 3) and your answer will be correct.
Answered by karthi
At what temperature will be the total kinetic energy of 0.30 moles of He be the same as total kinetic energy of 0.40 mole of Ar at 400 K ?
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