Asked by Carl

What would be the new temperature in Celsius of a sample of methane if 205 ml at 725 torr and 75.0 degrees C is allowed to change to 907 ml and 827 torr?

I used P1V1/T1=P2V2/T2
Plugged in the numbers (205)(725)/(348.15K)=(907)(827)/T2
When I solved for T2 I got 1.757*10^3, and I then subtracted 273.15 to get to Celsius.
Am I on the right track?
Please and thanks!
Answered by DrBob222
Carl, what's with all the names? Jim, Carl, George, Blaine et al. You confuse us when you do this and it makes it much harder to help you.
Answered by DrBob222
I didn't check the math but the procedure is correct and I see you converted all of the C to K first. That's good.
There are no AI answers yet. The ability to request AI answers is coming soon!