Question

A person can swim at a speed of 2 kilometers per hour in still water. If he heads across a river at right angles to current of 5 kilometers per hour, find his speed in relation to the land and the direction in which he actually moves.

Answer 1

speed^2 = 2^2 + 5^2

Θ is the angle downstream from directly across
... tan(Θ) = 2/5

Answer 2

Vr = X + Yi = 2 - 5i = 5.39km/h[-68.2o] = 5.39km/h[68.2o]S. of E.
= Resultant velocity and Direction.

Answer 3

post it.