Asked by jas

A man swim at a speed of 50m/min, swims 100m against the current and 100m with the current. if the time difference between the two times is 3min 45sec. find the speed of the current?
Answered by Steve
since time = distance/speed,

100/(50-x) = 100/(50+x) + 3.75

Now just find x.
Answered by John
In general, distance = rate x time
This case:
distance = (rate + current) x time

distance = (rate - current) x time

100 = (50 -c)(t)
100 = (50+c) (t + 3 3/4 minutes)

This should get you started.
Answered by Steve
You got your speeds reversed, John.

The slower speed takes longer.
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