Question
A man swim at a speed of 50m/min, swims 100m against the current and 100m with the current. if the time difference between the two times is 3min 45sec. find the speed of the current?
Answers
Steve
since time = distance/speed,
100/(50-x) = 100/(50+x) + 3.75
Now just find x.
100/(50-x) = 100/(50+x) + 3.75
Now just find x.
John
In general, distance = rate x time
This case:
distance = (rate + current) x time
distance = (rate - current) x time
100 = (50 -c)(t)
100 = (50+c) (t + 3 3/4 minutes)
This should get you started.
This case:
distance = (rate + current) x time
distance = (rate - current) x time
100 = (50 -c)(t)
100 = (50+c) (t + 3 3/4 minutes)
This should get you started.
Steve
You got your speeds reversed, John.
The slower speed takes longer.
The slower speed takes longer.