Question

Keisha and Kelly have an astronomy club devoted to observing the moon. If the moon is visible 28 out of 29 days and the girls can make it outside 14 days per 29 days, what is the probability they will go out on a night when the moon is not visible?

Answer 1

p(outside) = 14/29

p(not visible) = 1/29

probability of two independent events is the product of the individual probabilities

Answer 2

Thanks again Scott!