Asked by K
The two legs of a right triangle are in the ratio √3/2. If the hypotenuse is 10 units long, find the area (in square units) of the triangle. Please provide COMPLETE solution and FINAL ANSWER.
Answers
Answered by
Reiny
the sides would be √3x and 2x , then
(√3x)^2 + (2x)^2 = 10^2
3x^2 + 4x^2 = 100
solve for x and you have the two sides.
area = (1/2)(side1)(side2)
= ....
(√3x)^2 + (2x)^2 = 10^2
3x^2 + 4x^2 = 100
solve for x and you have the two sides.
area = (1/2)(side1)(side2)
= ....
Answered by
Steve
Hmmm. I see I misspoke before. I thought the sides were in the ratio √3.
So, let's go with what they gave you. If one side is 2x, then the other side is √3x
Now recall your Pythagorean Theorem. It says that
(2x)^2 + (√3x)^2 = 10^2
4x^2 + 3x^2 = 100
I know you want to just sit and wait for the answer, but I'm sure you can take it from here. One you have the two legs, it's easy to get the area.
So, let's go with what they gave you. If one side is 2x, then the other side is √3x
Now recall your Pythagorean Theorem. It says that
(2x)^2 + (√3x)^2 = 10^2
4x^2 + 3x^2 = 100
I know you want to just sit and wait for the answer, but I'm sure you can take it from here. One you have the two legs, it's easy to get the area.
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