1 mole of C8H18 ---> 8 mols of CO2
mol mass of C8H18 = 2*12 + 18 = 42 g/mol
so
(34.6/42) mol of C8H18
so
8(34.6/42) mol of CO2
mol mass of CO2 = 12 + 2*16 = 44 g/mol
so in the end
44 * 8 (34.6/42) grams of CO2
Calculate what Mass of CO2 is produced when 34.6g of C8H18 is burned in the air
1 answer