Asked by y912f

Find the distance using the appropriate arch length.
A television tower 520m high subtends an angle of 2deg30'. How far away is the tower?

some people that helped me alot were Reiny, Damon, bobpursley, and drwls..so i just wanna say thnks to you guys...are u guys math expersts or sometig
Answered by y912f
:)..can you also please explain how to do it
Answered by drwls
520m/(distance) = tan 2.5 degrees = 0.0437

Solve for the distance.
Answered by y912f
i don't get it ,,,why are there three different sides in the equation??
Answered by Damon
He just said that tan 2.5 deg was .0437
Answered by y912f
i get an answer that's not one of my choices..
A. 23m
B. 2300m
C. 11925m
D. 20850m
Answered by drwls
C. is the closest answer. The exact answer depends upon whether you are talking about the distance to the top or the base of the tower. If the top, use sin 2.5 instead of tan 2.5. That will get you an answer of 11921 m.

All of their choices have too many significant figures, considering that there are only three significant figures in 2.50 degrees
Answered by y912f
i got 11899
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