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The formation of CsCl from Cs(s) and Cl2(g) involves the following steps: 1. Cs(s)-Cs(g) 2. 1/2 Cl2(g)-Cl(g) 3. Cs(g) –Cs^+(g)...Question
The formation of CsCl from Cs(s) and Cl2(g) involves the following steps:
1.Cs(s)-Cs(g)
2.1/2 Cl2(g)-Cl(g)
3.Cs(g) –Cs^+(g) + e^-
4.Cl(g) + e^- - Cl^-(g)
5.Cs^+(g) +Cl^-(g)-CsCl(s)
Which of these steps absorb energy and which release energy?
1.Cs(s)-Cs(g)
2.1/2 Cl2(g)-Cl(g)
3.Cs(g) –Cs^+(g) + e^-
4.Cl(g) + e^- - Cl^-(g)
5.Cs^+(g) +Cl^-(g)-CsCl(s)
Which of these steps absorb energy and which release energy?
Answers
DrBob222
Can you not reason through some of these. For example, to convert Cs(s) to Cs(g) do you think it will take energy to do that or do you think it gives off energy? And for #2, do you think it will take energy to break a Cl-Cl bond or do you think it gives off energy when bonds are broken?
Give you answers and your reasoning and I shall be happy to check your answers.
Give you answers and your reasoning and I shall be happy to check your answers.