Question

Radio direction finders asre set up at points A and B, 8.68 mi apart on an east-west line. From A it is found that the bearing of a signal from a transmitter is N 54.3degE, while from B it is N 35.7degW. Find the distance of the transmitter from B, to the nearest hundredth of a mile.
i got 7.05mi

Answer 1

If you draw this, you have a triangle with ASA. With those two angles, you can get the third angleC.

Use the law of sines:
a/SinA=8.68/sinC
solve for side a.

I agree with your answer.

Answer 2

My diagram has triangle ABC with the interior angle at B equal to 54.3 and the interior angle at A equal to 35.7

(the bearings as given would not be inside the triangle as given)
BTW, angle C = 90

Your answer is what I got for the distance to A,
the distance to B would be 5.064

Answer 3

k thnks