Asked by K
A sample of NH4HS(s) is placed in a 2.61 −L flask containing 0.120 mol NH3(g).
NH4HS(s)⇌NH3(g)+H2S(g) Kp=0.108 at 25∘C
Part A
What will be the total gas pressure when equilibrium is established at 25∘C?
I'm getting P = 1.21atm which is wrong.
Can any1 please help. Thanks
NH4HS(s)⇌NH3(g)+H2S(g) Kp=0.108 at 25∘C
Part A
What will be the total gas pressure when equilibrium is established at 25∘C?
I'm getting P = 1.21atm which is wrong.
Can any1 please help. Thanks
Answers
Answered by
K
A sample of NH4HS(s) is placed in a 2.61 −L flask containing 0.120 mol NH3(g).
NH4HS(s)⇌NH3(g)+H2S(g) Kp=0.108 at 25∘C
Part A
What will be the total gas pressure when equilibrium is established at 25∘C?
I'm getting P = 1.21atm which is wrong.
Can any1 please help. Thanks
NH4HS(s)⇌NH3(g)+H2S(g) Kp=0.108 at 25∘C
Part A
What will be the total gas pressure when equilibrium is established at 25∘C?
I'm getting P = 1.21atm which is wrong.
Can any1 please help. Thanks
Answered by
DrBob222
Use PV = nRT and solve for p. That's approx 1.12 but you need a more accurate answer than that.
........NH4HS ==> NH3 + H2S
I.......solid.....1.12....0
C......solid.......+p....+p
E......solid.....1.l2+p...p
Write the expression for Kp, substitute the E line into Kp expression, solve the quadratic for p, then Ptotal = 1.12 + p + p = approx 1.31
........NH4HS ==> NH3 + H2S
I.......solid.....1.12....0
C......solid.......+p....+p
E......solid.....1.l2+p...p
Write the expression for Kp, substitute the E line into Kp expression, solve the quadratic for p, then Ptotal = 1.12 + p + p = approx 1.31
Answered by
X
WRONG
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