Asked by Steve
A sample of NH4HS(s) is placed in a 2.57 −L flask containing 0.140 mol NH3(g).
NH4HS(s)⇌NH3(g)+H2S(g)KP=0.108at25∘C
What will be the total gas pressure when equilibrium is established at 25∘C?
any idea on how to solve it like an outline?
Thanks
Answers
Answered by
DrBob222
Use PV = nRT and solve for pNH3 initially. Substitute pNH3 from this calculation into the below.
pNH3 is approx 1.5 but you need a more accurate number.
...........NH4HS ⇌ NH3 + H2S
I.........solid....1.5....0
C.........solid.....+x....x
E.........solid....1.3+x...x
Substitute the E line into the Kp expression and solve for x, then evaluate 1.5(or whatever that number is) +x
Ptotal = pNH3 + pH2S
pNH3 is approx 1.5 but you need a more accurate number.
...........NH4HS ⇌ NH3 + H2S
I.........solid....1.5....0
C.........solid.....+x....x
E.........solid....1.3+x...x
Substitute the E line into the Kp expression and solve for x, then evaluate 1.5(or whatever that number is) +x
Ptotal = pNH3 + pH2S
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