Asked by Josh

An elastic chord can be stretched to its elastic limit by a load of 8.0N. Assuming it gives an extension 250cm when a load of 0.4N is hung. What would be the chord length when a force of 2.8N is applied?
Answered by Henry
Length = 250cm/0.4N * 2.8N = cm.
Answered by Alfred
I want answer your
Answered by Alfred
Yes
Answered by Amarachi
Are there no answer to my question
Answered by Amarachi
Are there no answer to my question
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