Question

Find the probability of rolling an even number and then rolling a 6 when a number cube is rolled twice. Express the probability as percent rounded to 1 decimal place.

P(even and then a 6) =

Answer 1

The events are independent, so event A would be multiplied by event B. (Event A =rolling an even #) (Event B =rolling a 6).

The probability of event A = 1/2
The probability of event B = 1/6

To solve:

P(even then 6)= 1/2*1/6 = 1/12 = 0.083

Therefore, there is approximately 0.83*100 or 8.3% chance of rolling an even number (2 or 4 or 6) followed by a six with a six sided die.


Hope this helps :)

Answer 2

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Answer 3

No Problem!

Answer 4

I no understand