Asked by Chopsticks
What is the empirical forumla (lowest whole ratio) of the compounds below?
A.
13.0g Mg 1 mole/24.312 = .53 mole
87.0g Br 1 mole/79.909g = 1.09 mole
Mg .53/.53 Br 1.09/.53
Mg 1.0 Br 2.1
What do i do now?
A.
13.0g Mg 1 mole/24.312 = .53 mole
87.0g Br 1 mole/79.909g = 1.09 mole
Mg .53/.53 Br 1.09/.53
Mg 1.0 Br 2.1
What do i do now?
Answers
Answered by
DrBob222
I didn't check your math but if it's correct, round the 2.1 to 2.0 and the formula is Mg1Br2.0 or MgBr2.
Answered by
Anonymous
you just write it as MgBr2
Answered by
bobpursley
since when is 2.054 rounded up .
Round it to the nearest whole number
MgBr2
Round it to the nearest whole number
MgBr2
Answered by
Chopsticks
My teacher told me what I needed to get both numbers to whole numbers by mutiplying 2-6. But i do not know when to do it. Can you please give me an example
Answered by
bobpursley
http://books.google.com/books?id=EKOBuCwHh9wC&pg=PA29&lpg=PA29&dq=empirical+formula+C3H8&source=web&ots=2XWO2gHpDo&sig=CQMIhjMo-rkgb0Quz5KGGpXXQMs&hl=en&sa=X&oi=book_result&resnum=3&ct=result#PPA30,M1
See prob 3-2, where they had to multipy by 2 to get a whole number ratio
See prob 3-2, where they had to multipy by 2 to get a whole number ratio
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