Asked by sara
Determine the x and y components of the following three vectors in the xy plane.
1) A 19-m/s velocity vector that makes an angle of 40° counterclockwise from the -x direction.
x:
2) y:
Explain please!
1) A 19-m/s velocity vector that makes an angle of 40° counterclockwise from the -x direction.
x:
2) y:
Explain please!
Answers
Answered by
bobpursley
well, the x component is 19costheta, and the y component is 19sintheta.
draw the axis, measure the angle counterclockwise from x.
This is true for any angle, say 104. If the angle had been 104 deg
x=magnitude*cos104
y=magnitude*sin104
Caution: On geographical coordinates, a common convention is to measure angles from N, <b> clockwise</b>, even if the angle is given as xxx deg W of S. Convert that to degrees clockwise from N
N=magnitude*cosTheta
E=magnitude*sinTheta
and it will work regardless of the angle.
draw the axis, measure the angle counterclockwise from x.
This is true for any angle, say 104. If the angle had been 104 deg
x=magnitude*cos104
y=magnitude*sin104
Caution: On geographical coordinates, a common convention is to measure angles from N, <b> clockwise</b>, even if the angle is given as xxx deg W of S. Convert that to degrees clockwise from N
N=magnitude*cosTheta
E=magnitude*sinTheta
and it will work regardless of the angle.
Answered by
Henry
1. V = 19m/s[40o]S. of W. = 19[220o]CCW from +x-axis.
X = 19*Cos220 =
Y = 18*sin220 =
X = 19*Cos220 =
Y = 18*sin220 =
Answered by
Henry
Correcti0n: Y = 19*sin220 =
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