A blue ball is thrown upward with an initial speed of 21.0 m/s, from a height of 0.8 meters above the ground. 2.6 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 8.3 m/s from a height of 24.6 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2.

Question

1) What is the maximum height the blue ball reaches?

2) What is the height of the blue ball 1.9 seconds after the red ball is thrown?

3) How long after the red ball is thrown are the two balls in the air at the same height?

don't forget to write the answers please!

can you help me with this

Answer 1

first, produce the height equations.
Blue: 0.8 + 21.0t - 4.9t^2
Red: 24.6 - 8.3(t-2.6) - 4.9(t-2.6)^2
= 13.06 + 17.18t - 4.9t^2

Now you should be able to come up with the answers. Whatcha got?