Asked by Cam

A blue ball is thrown upward with an initial speed of 19.6 m/s, from a height of 0.5 meters above the ground. 2.4 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 7.9 m/s from a height of 22.1 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s^2.
One question..
How long after the blue ball is thrown are the two balls in the air at the same height?..and don't say it is .786 because that's only if they were released at the same time. Thanks
Answered by bobpursley
heightblue=.5+19.6t-4.9t^2
heightred=+22.1 -7.9(t-2.4)-4.9(t-2.4)^2

set these heights equal, solve for t. Have fun.
Answered by Cam
Hey bobpursley! ITS 3.09!! YAYY thanks lot!
Answered by diana
where did you get the 4.9
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