Question
A ball is thrown upward and returns to thrower hand in 12 seconds. What is speed with which ball is thrown and maximum height attained.
Answers
bobpursley
initial speed:
vf=vi+g5
but vf=-vi
-vi=vi-9.8t^2
vi=4.9*12^2
height:
at the top, vf=0
vf^2=vi^2+2ad
d=2vi/9.8 d is the same as hf
vf=vi+g5
but vf=-vi
-vi=vi-9.8t^2
vi=4.9*12^2
height:
at the top, vf=0
vf^2=vi^2+2ad
d=2vi/9.8 d is the same as hf