Question

A ball is thrown upward and has a velocity of 67.8 ft/s after 1.0s. After 3.0s, the ball's velocity is 3.4 ft/s. Find the acceleration (in ft/s2) and initial velocity (in ft/s) of the ball. Complete the equation of motion for the velocity of the ball:

v(t) = t +

Answer 1

in 2 seconds velocity decreases by 64.4 ft/s
a = change in v/change in time
= -64.4/2 = -32.2 ft/s^2
(which by the way is about g on earth)
v = 67.8 - 32.2 (t-1)
v = 100 -32.2 t