Solve the problem by making up an equation. A child is 12 years old, and his father is 32 years older. In how many years will the age of the father be 3 times the age of the child?

Just tell me the equation.

9 answers

y = 12 years
Child = y
Father = y + 32
Year of Father = x
Year difference = z

3x = y + 3(y + 32)
3x = 12 + 3(12 + 32)
3x = 144
x = 48
- - - - - - - - - -

z = x - (y + 32)
z = 48 - (12 + 32)
z = 48 - 44
z = 4

In 4 years, the age of the father will be 3 times the age of the child.

post it.

z = ((y + 3(y+32)) / 3) - (y + 32)

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