Asked by john

Solve the problem by making up an equation. A child is 12 years old, and his father is 32 years older. In how many years will the age of the father be 3 times the age of the child?
Just tell me the equation.
Answered by Anonymous
y = 12 years
Child = y
Father = y + 32
Year of Father = x
Year difference = z

3x = y + 3(y + 32)
3x = 12 + 3(12 + 32)
3x = 144
x = 48
- - - - - - - - - -

z = x - (y + 32)
z = 48 - (12 + 32)
z = 48 - 44
z = 4

In 4 years, the age of the father will be 3 times the age of the child.
Answered by Henry
post it.
Answered by Anonymous
z = ((y + 3(y+32)) / 3) - (y + 32)
Answered by Shamika
Say “HEY!” if your in RSM
Answered by Anonymous
What is the equation tho
Answered by literally nobody
can someone tell me what the equation is
Answered by Classified
HEY (I need the equation!)
Answered by nejire hado
uhm
Answered by mystery
hey (what is the equation)
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