Asked by john
Solve the problem by making up an equation. A child is 12 years old, and his father is 32 years older. In how many years will the age of the father be 3 times the age of the child?
Just tell me the equation.
Just tell me the equation.
Answers
Anonymous
y = 12 years
Child = y
Father = y + 32
Year of Father = x
Year difference = z
3x = y + 3(y + 32)
3x = 12 + 3(12 + 32)
3x = 144
x = 48
- - - - - - - - - -
z = x - (y + 32)
z = 48 - (12 + 32)
z = 48 - 44
z = 4
In 4 years, the age of the father will be 3 times the age of the child.
Child = y
Father = y + 32
Year of Father = x
Year difference = z
3x = y + 3(y + 32)
3x = 12 + 3(12 + 32)
3x = 144
x = 48
- - - - - - - - - -
z = x - (y + 32)
z = 48 - (12 + 32)
z = 48 - 44
z = 4
In 4 years, the age of the father will be 3 times the age of the child.
Henry
post it.
Anonymous
z = ((y + 3(y+32)) / 3) - (y + 32)
Shamika
Say “HEY!” if your in RSM
Anonymous
What is the equation tho
literally nobody
can someone tell me what the equation is
Classified
HEY (I need the equation!)
nejire hado
uhm
mystery
hey (what is the equation)