Asked by john
                Solve the problem by making up an equation. A child is 12 years old, and his father is 32 years older. In how many years will the age of the father be 3 times the age of the child?
Just tell me the equation.
            
        Just tell me the equation.
Answers
                    Answered by
            Anonymous
            
    y = 12 years
Child = y
Father = y + 32
Year of Father = x
Year difference = z
3x = y + 3(y + 32)
3x = 12 + 3(12 + 32)
3x = 144
x = 48
- - - - - - - - - -
z = x - (y + 32)
z = 48 - (12 + 32)
z = 48 - 44
z = 4
In 4 years, the age of the father will be 3 times the age of the child.
    
Child = y
Father = y + 32
Year of Father = x
Year difference = z
3x = y + 3(y + 32)
3x = 12 + 3(12 + 32)
3x = 144
x = 48
- - - - - - - - - -
z = x - (y + 32)
z = 48 - (12 + 32)
z = 48 - 44
z = 4
In 4 years, the age of the father will be 3 times the age of the child.
                    Answered by
            Henry
            
    post it.
    
                    Answered by
            Anonymous
            
    z = ((y + 3(y+32)) / 3) - (y + 32)
    
                    Answered by
            Shamika 
            
    Say “HEY!” if your in RSM
    
                    Answered by
            Anonymous
            
    What is the equation tho
    
                    Answered by
            literally nobody
            
    can someone tell me what the equation is
    
                    Answered by
            Classified
            
    HEY (I need the equation!)
    
                    Answered by
            nejire hado
            
    uhm
    
                    Answered by
            mystery
            
    hey (what is the equation)
    
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