Asked by Aline

1) If 9 and 12 each divide Q without remainder, which of the following must Q divide without remainder?
A)1
B)3
C)36
D)72
E)The answer can't be determined from the given info

^I got B

2) If mn does not equal 0, then 1/n^2 times (m^5n^3/m^3)^2

A)mn^4
B)m^4n^2
C)m^4n^3
D)m^4n^4
E)m^4n^5
^I got D

3) Out of a group of 3 female and 3 males, 3 people at random enter a room. What is the probability that there are exactly 2 males in the room?

A)1/4
B)3/8
C)9/20
D)2/3
E)5/6

^I got D

Answers

Answered by Damon
Q/9 = whole number
Q/12 = whole number

Q /(3*3) = whole number
Q/(2*2*3) = whole number

Q at least 3*3*2*2 = 9*4 =36
of course 72 would also work :)
Answered by Damon
2. so did I
Answered by bobpursley
wrong on the third.
Answered by Damon

p(male) = .5
p(not male) = .5
P(2 out of 3) = C(3,2) .5^2 *.5^1
= 3!/[(1!)2!]*.5^3
=3 *.5^3 = .375 = 1/[2 2/3) = 1/ (8/3) = 3/8

Answered by Aline
For number 1, wouldn't it be none of them?

And if number 4 is wrong, then can you please explain?
Answered by Aline
Opps! sorry thank you!!
Answered by Damon
Did I not do so ?
And I said two of them work for number 1, neither of which you picked.
Answered by Damon
You are welcome.
Answered by Damon
Changed my ind about #4
Not binomial because p is not constant

try MMF , MFM , FMM
MMF = 3/6 * 2/5 * 3/4 = 3/20
MFM = 3/6 * 3/5 * 2/4 = 3/20
FMM = 3/6 * 3/5 * 2/4 = 3/20
sum = 9/20
Answered by Aline
ohh Okay
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