x = my + b
a. for the x-intercept isn't y = 0?
so x = b
b. change it to the y-intercept - slope form
my = x - b
y = (1/m)x - b/m
so the slope is 1/m
A line has the equation x = my + b for some real nonzero constants m and b.
a. In terms of m and/or b, what is the x-intercept of this line?
b. In terms of m and/pr b, what is the slope of this line?
I have no idea how to solve this, so please walk me through to the answer.
Thanks in advance!
3 answers
I understand it now.
symbolab