Question

Please help me to solve this word problem. How do I write and equation and solve? Find three consecutive even integers such that 50 times the smallest is 88 less than 46 times the largest

Answer 1

a = smallest number

b = middle number = a + 2

c = largest number = b + 2 = a + 2 + 2 = a + 4


50 times the smallest is 88 less than 46 times the largest, mean:

50 a = 46 c - 88

Now:

50 a = 46 ( a + 4 ) - 88

50 a = 46 ∙ a + 46 ∙ 4 - 88

50 a = 46 a + 184 - 88

50 a = 46 a + 96

Subtract 46 a

to both sides

50 a - 46 a = 46 a + 96 - 46 a

4 a = 96

Divide both sides by 4

a = 96 / 4 = 24

b = a + 2 = 24 + 2 = 26

c = a + 4 = 24 + 4 = 28

The numbers are:

24 , 26 and 28