Asked by Mikey
Please help me to solve this word problem. How do I write and equation and solve? Find three consecutive even integers such that 50 times the smallest is 88 less than 46 times the largest
Answers
Answered by
Bosnian
a = smallest number
b = middle number = a + 2
c = largest number = b + 2 = a + 2 + 2 = a + 4
50 times the smallest is 88 less than 46 times the largest, mean:
50 a = 46 c - 88
Now:
50 a = 46 ( a + 4 ) - 88
50 a = 46 ∙ a + 46 ∙ 4 - 88
50 a = 46 a + 184 - 88
50 a = 46 a + 96
Subtract 46 a
to both sides
50 a - 46 a = 46 a + 96 - 46 a
4 a = 96
Divide both sides by 4
a = 96 / 4 = 24
b = a + 2 = 24 + 2 = 26
c = a + 4 = 24 + 4 = 28
The numbers are:
24 , 26 and 28
b = middle number = a + 2
c = largest number = b + 2 = a + 2 + 2 = a + 4
50 times the smallest is 88 less than 46 times the largest, mean:
50 a = 46 c - 88
Now:
50 a = 46 ( a + 4 ) - 88
50 a = 46 ∙ a + 46 ∙ 4 - 88
50 a = 46 a + 184 - 88
50 a = 46 a + 96
Subtract 46 a
to both sides
50 a - 46 a = 46 a + 96 - 46 a
4 a = 96
Divide both sides by 4
a = 96 / 4 = 24
b = a + 2 = 24 + 2 = 26
c = a + 4 = 24 + 4 = 28
The numbers are:
24 , 26 and 28
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