Asked by Dallas
Charley has a bag of color tiles. In Charley's bag there are 15 red tiles, 4 blue tiles, 1 yellow tile, and 30 green tiles. Charley removed one tile from the bag, then a second tile, and a third tile. What is the probability that the tiles came out as 1 red, 1 green, and then 1 blue in that order?
Answers
Answered by
Damon
50 tiles in all to start
1 red:
15/50 = 3/10
now 49 tiles
1 green:
30/49
now 48 tiles
now 1 blue
4/48 = 1/12
so
3/10 * 30/49 * 1/12
1 red:
15/50 = 3/10
now 49 tiles
1 green:
30/49
now 48 tiles
now 1 blue
4/48 = 1/12
so
3/10 * 30/49 * 1/12
Answered by
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find the probability of pulling the outcome 2 x in row with replacing the tiles after each pull .p(blue)
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