Asked by Baron
A water pump of 1.2kilowatts rating,pumps 480g of water into an over head tank at a height of 5m in 30 seconds. What is d efficiency of d time
Answers
Answered by
Damon
m = 0.48 kg are you sure you mean grams?
You do not usually use a pump that powerful for so little mass. (about a horsepower to move one pound up 15 feet in 30 seconds.)
power in = 1200 Watts
energy in = 1200 *30 Joules
work out = 0.48 * 9.81 * 5 Joules
so eff = work out/energy in
= 0.48*9.81*5/(1200*30)
= 6.54 * 10^-4
I think you may mean 480 kg
You do not usually use a pump that powerful for so little mass. (about a horsepower to move one pound up 15 feet in 30 seconds.)
power in = 1200 Watts
energy in = 1200 *30 Joules
work out = 0.48 * 9.81 * 5 Joules
so eff = work out/energy in
= 0.48*9.81*5/(1200*30)
= 6.54 * 10^-4
I think you may mean 480 kg
Answered by
Henry
Mass = 480kg?
F = M*g = 480 * 9.8 = 4704 N.
Po = F*d/t = 4704 * 5/30 = 784 J./s = 784 Watts. = Power out.
Eff. = Po/Pi = 784/1200 = 0.653 = 65.3%.
F = M*g = 480 * 9.8 = 4704 N.
Po = F*d/t = 4704 * 5/30 = 784 J./s = 784 Watts. = Power out.
Eff. = Po/Pi = 784/1200 = 0.653 = 65.3%.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.