If an arrow is shot upward on Mars with a speed of 52 m/s, its height in meters t seconds later is given by
y = 52t − 1.86t2.
(Round your answers to two decimal places.)
(i) [1, 2]
(ii) [1, 1.5]
(iii) [1, 1.1]
(iv) [1, 1.01]
(v) [1, 1.001]
3 answers
what is the question?
Find the average speed over the given time intervals.
ok, avg speed=
=(y(finaltime)-y(initialtime)) divided by(finaltime-initialtime)
y = 52t − 1.86t2.
lets do iv)
y(1)=52-1.86=51.14
y(1.001)=52.052-1.86(1.001)^2=50.188
so avg apeed= (.188)/.001=188m/s
=(y(finaltime)-y(initialtime)) divided by(finaltime-initialtime)
y = 52t − 1.86t2.
lets do iv)
y(1)=52-1.86=51.14
y(1.001)=52.052-1.86(1.001)^2=50.188
so avg apeed= (.188)/.001=188m/s
3 answers