Also, for question 2, on how to make 500 ml of a 2M sol'n of NaOH?
-Wouldn't you have to take 2 M of the NaOH solution and then dissolve however many (g) of NaOH in 500 ml of water?
So, 500 ml/1,000 = 0.5 L
2M = moles of solute/ 0.5 L solution = to get 1 mol of solute
How would you explain that qualitatively?
How would you prepare 10L of 0.3M KH2 PO4? FW of KH2 PO4= 136.09g
Before you make the solution, wouldn't you find how much solute there is first. So by using the M=moles of solute / V ?
Then, you would add that amount of solute to the L of solution.
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