Asked by sze
Consider the function f(x) = 3-3 x^{2/3} on the interval [ -1 , 1 ].
Which of the three hypotheses of Rolle's Theorem fails for this function on the inverval?
(a) f(x) is continuous on [-1,1].
(b) f(x) is differentiable on (-1,1).
(c) f(-1)=f(1).
Answer:( a, b, or c )
Which of the three hypotheses of Rolle's Theorem fails for this function on the inverval?
(a) f(x) is continuous on [-1,1].
(b) f(x) is differentiable on (-1,1).
(c) f(-1)=f(1).
Answer:( a, b, or c )
Answers
Answered by
Damon
dy/dx = -3*(2/3)x^-(2/3) =-2/x^(2/3)
which is undefined at x = 0
which is undefined at x = 0
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