Asked by Anonymous
Swiss cheese and Limburger cheese cost different amounts per pound, but you do not know how much. A box containing 3 pounds of Swiss and 2 pounds of limburger costs 24.40 dollar. Another box containing 4 pounds of Swiss and 5 pounds of Limburger costs 47.70 dollars. Assuming that these figures are for the cheese only (not for the box), how much does the Swiss cheese cost per pound?
Answers
Answered by
PsyDAG
3S + 2L = 24.40
4S + 5L = 47.70
Multiply the first equation by 5 and the second by 2.
15S + 10L = 122
8S + 10L = 95.40
Subtract the second equation from the first.
7S = 26.60
Divide both sides by 7.
4S + 5L = 47.70
Multiply the first equation by 5 and the second by 2.
15S + 10L = 122
8S + 10L = 95.40
Subtract the second equation from the first.
7S = 26.60
Divide both sides by 7.
Answered by
Steve
If the costs are L and S, then we are told that
3S+2L = 24.40
4S+5L = 47.70
or,
15S+10L = 122.00
8S+10L = 95.40
subtract and you get
7S = 26.60
S = 3.80
This seems for comfortable than direct substitution.
3S+2L = 24.40, so
L = 12.20 - 1.5S
4S+5L = 47.70
4S+5(12.20-1.5S) = 47.70
-3.5S = -13.30
S = 3.80
3S+2L = 24.40
4S+5L = 47.70
or,
15S+10L = 122.00
8S+10L = 95.40
subtract and you get
7S = 26.60
S = 3.80
This seems for comfortable than direct substitution.
3S+2L = 24.40, so
L = 12.20 - 1.5S
4S+5L = 47.70
4S+5(12.20-1.5S) = 47.70
-3.5S = -13.30
S = 3.80
Answered by
g
guig
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