Asked by Anonymous
                The middle bead in a string of 17 beads was the largest and most expensive. Starting from each end, the end beads were $1 each and each bead is $1 more that the one before it, up the middle. If the string beads is worth $100, what is the middle bead worth?
            
            
        Answers
                    Answered by
            Steve
            
    the middle bead is #9. So, you have two AP's of 8 terms each, plus the middle bead. That means that 
2(8/2 (2+7))+ x = 100
x = 28
    
2(8/2 (2+7))+ x = 100
x = 28
                    Answered by
            Damon
            
    8 1 8
https://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html
first 8 of arithmetic sequence
a = 1
d = 1
sum from n = 1 to n = 8
Xn = a + d(n-1)
sum =(n/2)[2a+(n-1)d]
= (8/2)[2+7]=72/2
we want twice that to include the other 8
= 72
now that middle one
100 - 72 = 28
    
https://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html
first 8 of arithmetic sequence
a = 1
d = 1
sum from n = 1 to n = 8
Xn = a + d(n-1)
sum =(n/2)[2a+(n-1)d]
= (8/2)[2+7]=72/2
we want twice that to include the other 8
= 72
now that middle one
100 - 72 = 28
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.