Asked by Monica
A bead of mass m = 33.5 kg is released from point A which is located 5 m above the ground and slides on a frictionless track. Determine the bead's speed when it reaches point C which is located 2.0 m above the ground.
Answers
Answered by
Damon
falls 3 meters
(1/2) m v^2 = m g (3)
v^2 = 2 mg(3)
v = sqrt (2 m g(3)
You should remember forever
This:
when something falls distance h from zero speed at top and no air drag
v = sqrt (2 g h)
mass does not matter for this
(1/2) m v^2 = m g (3)
v^2 = 2 mg(3)
v = sqrt (2 m g(3)
You should remember forever
This:
when something falls distance h from zero speed at top and no air drag
v = sqrt (2 g h)
mass does not matter for this
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