Asked by supercute
ne kilogram of ice of density 1000 kg m–3 is frozen in the shape of a cube. The diameter of a water molecule is 10–10 m. What is the difference in the orders of magnitude of the length of one side of the ice cube and the diameter of a water molecule?
please and thank u
please and thank u
Answers
Answered by
davonte
The volume of 1kg ice is:
V = mass/density = 1/1000 = 10⁻³ m³
A cube with sides of length L has a volume = L³
So for the ice cube:
L³ = 10⁻³
L = ∛(10⁻³) = 10⁻¹m
The ratio (length of ice cube)/(diameter of molecule)
= (10⁻¹)/(10⁻¹⁰)
= 10⁹
We say the length of a side of the ice cube is
*** 9 orders of magnitude ***
bigger than the diameter of the water molecule.
Or we can say there are 9 orders of magnitude difference between the length of one side of the ice cube and the diameter of a water molecule.
V = mass/density = 1/1000 = 10⁻³ m³
A cube with sides of length L has a volume = L³
So for the ice cube:
L³ = 10⁻³
L = ∛(10⁻³) = 10⁻¹m
The ratio (length of ice cube)/(diameter of molecule)
= (10⁻¹)/(10⁻¹⁰)
= 10⁹
We say the length of a side of the ice cube is
*** 9 orders of magnitude ***
bigger than the diameter of the water molecule.
Or we can say there are 9 orders of magnitude difference between the length of one side of the ice cube and the diameter of a water molecule.
Answered by
Ms. Sue
flirty me/ supercute -- please keep the same name for your posts.
Answered by
bobpursley
use the second phrase.
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