Asked by JC
a 15-kilogram box is dragged up an incline that is 8.0 meters long and makes an angle of 15 degrees with the horizontal. If the coefficient of friction between the box and the incline is .40, calculate the amount of work done by the applied force.
Answers
Answered by
bobpursley
It is rather easy:
work= PE change+friction work
= mg8sin15 + 8*mg*CosTheta*.4
check that.
work= PE change+friction work
= mg8sin15 + 8*mg*CosTheta*.4
check that.
Answered by
JC
worked thanks...
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