Asked by flirtyme
The efficiency of an electric motor is 20 %. When lifting a body 500 J of energy are wasted. What is the useful work done by the motor?
please and thank u!
please and thank u!
Answers
Answered by
bobpursley
1/5 Effort=500
Effort=2500J
useful work=2500-500=???
Effort=2500J
useful work=2500-500=???
Answered by
flirtyme
sir, the answer is supposed to be 125?? is there something wrong
Answered by
Henry
Eff. = Eo/Ei = 0.2.
Eff. = Eo/(Eo+500) = 0.2.
Eo = 0.2Eo+100,
0.8Eo = 100,
Eo = 125J. = Energy out = Useful work.
Eff. = Eo/(Eo+500) = 0.2.
Eo = 0.2Eo+100,
0.8Eo = 100,
Eo = 125J. = Energy out = Useful work.
Answered by
AYO HENRY
HENRY THANK YOU MAN
Answered by
Concetta
Thanks a lot, Terrific information.
thesis writing service
writing service
thesis writing service
writing service
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.