Asked by anonymous
Acetic acid (CH_3COOH) is a weak acid.
a) Write the symbolic equation showing the ionisation of acetic acid.
b)Given that an acetic acid solution of pH 4.8 has a hydrogen ion concentration of 1.58 * 10^-5 mol L^-1, what is the concentration of the acetate ion at equilibrium?
c) Calculate the equilibrium concentration of the undissociated CH_3COOH if the equilibrium constant for this dissociation is 1.8 * 10^-5
a) Write the symbolic equation showing the ionisation of acetic acid.
b)Given that an acetic acid solution of pH 4.8 has a hydrogen ion concentration of 1.58 * 10^-5 mol L^-1, what is the concentration of the acetate ion at equilibrium?
c) Calculate the equilibrium concentration of the undissociated CH_3COOH if the equilibrium constant for this dissociation is 1.8 * 10^-5
Answers
Answered by
DrBob222
a. acetic acid is HAc to save typing.
HAc + H2O ==> H3O^+ + Ac^-
b.
Convert pH = 4.8 to H3O^+. Since the answer to a shows 1 Ac to 1 H3O, then H3O = Ac
c.
Write Ka expression for HAc. Substitute H3O^+ and Ac^- and solve for (HAc).
Post your work if you get stuck.
HAc + H2O ==> H3O^+ + Ac^-
b.
Convert pH = 4.8 to H3O^+. Since the answer to a shows 1 Ac to 1 H3O, then H3O = Ac
c.
Write Ka expression for HAc. Substitute H3O^+ and Ac^- and solve for (HAc).
Post your work if you get stuck.
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