Asked by Anonymous

Find how many integers between 200 and 500 are divisible by 8

Answers

Answered by Arora
You can solve this problem as an Arithmetic Progression.

The series: 208, 216, 224,...., 488, 496

a(n) = 496
a(1) = 208
d = 8

For an A.P.,
a(n) = a(1) + (n-1)d
=> 496 = 208 + (n-1)8
=> 288/8 = n - 1
=> n = 36 + 1 = 37

Hence, there are 37 such integers.
Answered by Bosnian
Find the first number in thist interval that is divisible by 8

In this case:

200 / 8 = 25

Find the last number in thist interval that is divisible by 8

In this case:

496 / 8 = 62

Numbers 200 and 496 assume arithmetic progression, where first member a1 = 200 and last member a62 = 496

Common difference is d = 8

In arithmetic progression:

an = a1 + ( n - 1 ) d

In this case:

a62 = a1 + ( n - 1 ) d

496 = 200 + ( n - 1 ) ∙ 8

496 = 200 + 8 n - 8

496 = 192 + 8 n

Subtract 192 to both sides

496 - 192 = 192 + 8 n - 192

304 = 8 n

Divide both sides by 8

38 = n

n = 38



Answered by Arora
200 shouldn't be included, should it?

The question says 'between 200 and 500', so.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions