Asked by Gie

Find some integers having 10 divisors.
Answered by bobpursley
what about 2x3x5x7x11x13x17x19....up to 10 prime numbers...that will get you more than 10
you can see from the first few, you also as a side, you get 6,10,14...15,21,33,...
Answered by Steve
If you want exactly 10 divisors, then the number will have to be a product of two primes, one raised to the 1st power, and the other raised to the 4th power.

For example,

567 = 3^4 * 7^1
Its factors are
1 3 7 9 21 27 63 81 189 567

see why at

http://www.wikihow.com/Find-How-Many-Factors-Are-in-a-Number
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