Question

Suppose f(x)=|P(x)|. Determine the range of f

(1,-3), (4,1), (3,3), (2,4), (-2,4), (-3,5), (-1,6)

Algebra 1 - Damon today at 10:12am
Nothing can be negative.
No y can be different from x

Can you explain further please

Answer 1

If f(x) is equal to the absolute value of another quanity, then no f(x) can be negative, by definition. (1,-3) f(x) cannot be -3.

Answer 2

If the points given are those of P(x), then f(x) has the same values, with the exception of (1,-3). f(x) contains (1,3) since |-3|=3, and the range of f(x) is all the distinct values of y.