Question

S) Suppose we want to determine the (binomial) probability (p) of getting 5 heads in 15 flips of a 2-sided coin. Using the Binomial table in the appendix of the text, what values of n, x, and p would we use to look up this probability, and what would be the probability?

n=total number of trials=15 flips

x= number of successes desired=5 heads

p= is the probably of failure=.5 (2 sided coin is 1 out of 2, 1/2=.50)

Using the Binomial table, the probability should be .092

*** I am not very sure of my answer! Any help would be appreciated***

Answer 1

This is a standard question in binomial distribution.
I don't know what your tables in your text look like, but I would do:

prob (getting 5 heads in 15 flips)
= C(15,5)(1/2)^5 (1/5)^10
= 3003(1/2)^15
= 3003/32768 = appr .0916 or your answer of .092

You are correct