Asked by Eka
Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$.
Determine $p(x)$ (in expanded form).
Determine $p(x)$ (in expanded form).
Answers
Answered by
sam
john is 30 pounds heavier than peter. their total weight 235 pounds.find johns weight
Answered by
Steve
peter is 30 lbs lighter than john. So,
j + j-30 = 235
Odd; I expected an integer answer...
as for the polynomial, who knows? I see no question there. And LaTex doesn't do well here. And p(x) cannot be monic with real coefficients and have a complex root.
j + j-30 = 235
Odd; I expected an integer answer...
as for the polynomial, who knows? I see no question there. And LaTex doesn't do well here. And p(x) cannot be monic with real coefficients and have a complex root.
Answered by
Steve
ah, actually I misspoke.
Since 3+2i is also a root, we have
p(x) = (x-(3-2i))(x-(3+2i))(x-a)
= (x^2-6x+13)(x-a)
So, now just solve for a:
p(0) = -13a = -52
a = 4
p(x) = (x^2-6x+13)(x-4) = x^3-10x^2+37x-52
Since 3+2i is also a root, we have
p(x) = (x-(3-2i))(x-(3+2i))(x-a)
= (x^2-6x+13)(x-a)
So, now just solve for a:
p(0) = -13a = -52
a = 4
p(x) = (x^2-6x+13)(x-4) = x^3-10x^2+37x-52
Answered by
Eka
Thanks so much :)
Answered by
gg
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Answered by
Anonymous
Chunky Kong
Answered by
Stun Zeed
yes
Answered by
#TheDramaIsReal
I love how this started with math and out of nowhere came a 1v1 request
Answered by
ur mom
ur mom
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