Asked by Anonymous
In an aluminum calorimeter, 25.00 g of I2 was burned in excess H2 to form HI. From the data below, establish the molar heat of reaction and write a thermochemical reaction.
Data:
Mass I2 25.00 g
Mass Al 70.00 g
Specific heat Al 0.900 J/gC
Volume water 100.0 mL
Initial temperature 34.6C
Final temperature 23.8C
Data:
Mass I2 25.00 g
Mass Al 70.00 g
Specific heat Al 0.900 J/gC
Volume water 100.0 mL
Initial temperature 34.6C
Final temperature 23.8C
Answers
Answered by
bobpursley
I2+...? 2HI
so for each mole of I2 burned, two moles of HI is achieved.
molesI2=25/127
Heatfrom I2 + HeatgainedbyAl + heatgainedwater=0
HeatfromI2+70(.900)(23.8-34.6) +200*4.19*(23.8-34.6)=0
solve for HeatfromI2
molareatofrecton for I2=heatfromI2 /2
that is the heat per mole of HI formed
so for each mole of I2 burned, two moles of HI is achieved.
molesI2=25/127
Heatfrom I2 + HeatgainedbyAl + heatgainedwater=0
HeatfromI2+70(.900)(23.8-34.6) +200*4.19*(23.8-34.6)=0
solve for HeatfromI2
molareatofrecton for I2=heatfromI2 /2
that is the heat per mole of HI formed
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.