Question
A calorimeter contains 50.0 mL of water; both are at 21.2 degrees C. Then the 50.0 mL of water at 57.6 degrees C is added to the calorimeter. At equilibrium, the final temperature of the water and the calorimeter is 33.3 degrees C. Calculate the heat capacity, C, of the calorimeter.
Answers
[Ccal x (Tfinal-Tinitia)] + [mass Cal H2O x specific heat H2O x (Tfinal-Tinitial)] + [mass warm H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute and solve for Ccal.
Substitute and solve for Ccal.
Related Questions
How much heat energy in KJ is evolved by a reaction in a calorimeter in which the temperature of the...
A 53.31-g sample of water at 88.8 degrees C is added to a sample of water at 23.9 degrees C in a con...
A 40.0 g block of ice at -15 degrees C is dropped into a calorimeter (of negligible heat capacity) c...
Data and Calculations:
1. Volume of water in calorimeter: 100.0 mL
2. Mass of water in calorimet...