a(n) = a(1) + (n-1)d
a(9) = a(1) + (9-1)d
You have a(9), you have d
Use those to get a(1) from the above mentioned.
Then, plug those values into the sum formula I mentioned on the other question.
I swear, last question!
Calculate S(31) for the arithmetic sequence in which a(9) = 17 and the common difference is d = -2.1
-46
-29.2
32.7
71.3
Usually, I can figure these out but I'm stuck:(
4 answers
Ok, I'm so sorry, but I got so lost.
For some reason, (I think) I'm getting it wrong at determining a(1).
I don't know what the heck I'm doing, but I've gotten either 5.9, -5.9, or 11.1 for a(1) and none of them work for the other formula. I feel super dumb right now, is there any chance you could show me again how to get a(1)? Sorry
For some reason, (I think) I'm getting it wrong at determining a(1).
I don't know what the heck I'm doing, but I've gotten either 5.9, -5.9, or 11.1 for a(1) and none of them work for the other formula. I feel super dumb right now, is there any chance you could show me again how to get a(1)? Sorry
Wait-- I made a dumb typo. I think it's 71.3 (oh my gosh I'm dying)
a(9) = a(1) + (n-1)d
a(9) = 17, d = -2.1
17 = a(1) + (9-1)*-2.1
a(1) = 17 + 16.8
= 33.8
S(31) = (n/2)[2a(1) + (n-1)d]
= (31/2)[2(33.8) + 30(-2.1)]
= (31/2)(67.6 - 63)
= (31/2)(4.6)
= 31*2.3
= 71.3
Yes, you're correct
a(9) = 17, d = -2.1
17 = a(1) + (9-1)*-2.1
a(1) = 17 + 16.8
= 33.8
S(31) = (n/2)[2a(1) + (n-1)d]
= (31/2)[2(33.8) + 30(-2.1)]
= (31/2)(67.6 - 63)
= (31/2)(4.6)
= 31*2.3
= 71.3
Yes, you're correct