Asked by anonymous
An 85kg person bounces on a bathroom scale having a force constant of 1.50*10^6 N/m. The amplitude of the bounce is 0.200 cm. What is the maximum energy stored in the spring?
I use the formula mg = kx, solved for x, and got 5.55333 * 10^-4.
Then I added the amplitude, .002 m, to get 2.5553*10^-3, which was wrong. I also tried the answer without adding the amplitude, and that was wrong.
Where could I be going wrong? There was some discussion on the forum of my online class saying that the question might have some issues...where is the error here?
Thank you.
I use the formula mg = kx, solved for x, and got 5.55333 * 10^-4.
Then I added the amplitude, .002 m, to get 2.5553*10^-3, which was wrong. I also tried the answer without adding the amplitude, and that was wrong.
Where could I be going wrong? There was some discussion on the forum of my online class saying that the question might have some issues...where is the error here?
Thank you.
Answers
Answered by
bobpursley
ω = sqrt(k/m) = sqrt(1.5e6/85) = 133rad/s
x(t) = 0.002sinωt = (1/500)*sinωt
v(t) = (ω/500)*cosωt
vmax = (ω/500) = 133/500=0.266 m/s
max energy= 1/2 m vmax^2
you know m, and vmax.
check my math.
x(t) = 0.002sinωt = (1/500)*sinωt
v(t) = (ω/500)*cosωt
vmax = (ω/500) = 133/500=0.266 m/s
max energy= 1/2 m vmax^2
you know m, and vmax.
check my math.
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