Asked by uzoma
the sides of an equilateral triangle is as follows. 3a+2, 3b-a and b+3. find the value of a, b and the perimeter of the triangle
Answers
Answered by
Reiny
They are all equal, so
set pairs equal.
1st and last ---> 3a+2 = b+3 or 3a - b = 1 **
2nd and last ---> 3b - a = b+3 or a - 2b = -3 ***
from ** , b = 3a-1
sub into ***
a - 2(3a-1) = -3
a - 6a + 2 = -3
-5a = -5
a = 1 , then b = 3-1 = 2
the sides are 5 units each
and the perimeter would be .....
set pairs equal.
1st and last ---> 3a+2 = b+3 or 3a - b = 1 **
2nd and last ---> 3b - a = b+3 or a - 2b = -3 ***
from ** , b = 3a-1
sub into ***
a - 2(3a-1) = -3
a - 6a + 2 = -3
-5a = -5
a = 1 , then b = 3-1 = 2
the sides are 5 units each
and the perimeter would be .....
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