Asked by Ann
2 sides of an equilateral triangle measure (y+10) units and (y^2-2) units. If the perimeter of the triangle is 21 units, what is the value of y?
I was trying (y+(y+10) + (y^2-2)=21
got to y^2+2y+-13 and wasn't sure how to proceed.
Or should I take a side (y^2-2)*3=21?
I ended up with 3 but the other side ends up with -3. Could this be a typo?
I was trying (y+(y+10) + (y^2-2)=21
got to y^2+2y+-13 and wasn't sure how to proceed.
Or should I take a side (y^2-2)*3=21?
I ended up with 3 but the other side ends up with -3. Could this be a typo?
Answers
Answered by
Steve
It appears that the 3rd side is y, so yes, that means
y + (y+10) + (y^2-2) = 21
y^2+2y+8 = 21
y^2+2y-13 = 0
now use the quadratic formula. If you want an integer or rational answer, there must be a typo somewhere.
y + (y+10) + (y^2-2) = 21
y^2+2y+8 = 21
y^2+2y-13 = 0
now use the quadratic formula. If you want an integer or rational answer, there must be a typo somewhere.
Answered by
Miranda
You know the perimeter is 21 and, it's equilateral. Which means all sides are equal so therefor 21 divided by 3 = 7.
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