Asked by Anonymous
A ship moved from point B 12km away on a bearing of N035E.it then moved westward to another point c20km which is on the bearing of N052w.calculate the distance /bc/
Answers
Answered by
Steve
Call A the point 12km from B, where the ship turned west. Then the angle BAC is 65°. Now just use the law of cosines to find BC:
BC^2 = 12^2 + 20^2 - 2*12*20*cos65°
BC^2 = 12^2 + 20^2 - 2*12*20*cos65°
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