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A bullet of mass 3.9 g was fired at a stationary ball of lead. The head on impact moved the 10 kg ball at a velocity of .3703 m...Asked by colton
a bullet of mass 5.0g was fired at a stationary ball of lead. the head on impact moved the 10 kg ball at a velocity of .50m/s. of energy losses due heat the internal energy are ignored, what was the speed of the bullet?
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Answered by
Arora
You will use the conservation of momentum for this question.
Mass of bullet = m = 0.005kg
Mass of ball of lead = M = 10kg
Initial speed of bullet = u
Final combined speed = v = 0.5m/s
As per conservation of momentum,
mu = (M+m)v
=> (0.005)u = (0.005+10)(0.5)
=> u = (10.005)(100)
=> u = 1000.5 m/s
Hence, the original speed was 1000.5 m/s
Mass of bullet = m = 0.005kg
Mass of ball of lead = M = 10kg
Initial speed of bullet = u
Final combined speed = v = 0.5m/s
As per conservation of momentum,
mu = (M+m)v
=> (0.005)u = (0.005+10)(0.5)
=> u = (10.005)(100)
=> u = 1000.5 m/s
Hence, the original speed was 1000.5 m/s